如何用C语言计算1！+2！+·····n!值

1、用for循环来计算

#include<stdio.h>

int main()

{

int n,b,c,x,y;

y=0;

printf("请输入一个数：");

scanf("%d",&n);

for(b=1;b<n+1;b++)

{

for(c=1,x=1;c<=b;c++)

x=x*c;

y=y+x;

}

printf("1！+2！+·····%d!的值为：%d\n",n,y);

return 0;

}

1、用for循环+while循环来完成

#include<stdio.h>

int main()

{

int n,b,c,x,y;

y=0;

printf("请输入一个数：");

scanf("%d",&n);

for(b=1;b<n+1;b++)xiangqieqieru

{c=1;

x=1;

while(c<=b)

{ x=x*c;

c++;

}

y=y+x;

}

printf("1！+2！+·····%d!的值为：%d\n",n,y);

return 0;

}